Sin@ - Cos@ + 1/Sin@ + Cos@ - 1 = Sec @ + Tan@
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Answered by
8
hope this answer will help you.
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Anonymous:
Hey, mate had u got righteous answer of this question?
Answered by
0
Heya!!
L.H.S
=>
(Cos x/2 + Sin x/2)² - (Cos² x/2 - Sin²x/2)
_____________________________
(Cosx/2 - Sinx/2)² + (Cos²x/2 - Sin²x/2)
=>
Cosx/2 + Sinx/2
________________ { Tanx/2 }
Cosx/2 - Sinx/2
=>
Tanx/2 × Tan ( 45 + x/2 )
R.H.S
Sec x + Tan x
=>
1 + Sin x / Cos x
=>
( Cos x/2 + Sin x/2 )²
___________________
( Cos² x/2 - Sin² x/2 )
=>
( Cos x/2 + Sin x/2 )
___________________
( Cos x/2 - Sin x/2 )
=>
Tan ( 45 + x/2 )
L.H.S ≠ R.H.S
I think something is missing in the given question.
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