Question

sin@+cos@=underfoot sin(90-@) find cot@

Answer 1

$\bf HELLO DEAR,$


sin@ + cos@ = √2sin(90 - @)

sin@ + cos@ = √2cos@
on squaring both side,

(sin²@ + cos²@) + 2sin@cos@ = 2cos²@

1+ 2sin@cos@ = 2(1 - sin²@)

1 + 2sin@cos@ = 2 - 2sin²@

2sin²@ = 2 - 1 - 2sin@cos@

2sin²@ = (1 - 2sin@cos@)

2sin²@ = (sin²@ + cos²@ - 2sin@cos@)

2sin²@ = (sin@ - cos@)²

√2sin@ = (sin@ - cos@)

√2 = (sin@ - cos@)/sin@

√2 = 1 - cot@

(1 - √2) = cot@



I HOPE ITS HELP YOU DEAR,
THANKS