Math, asked by baibaswatnaik, 10 months ago

SinB/sinA +2cos(A+B)= sin(2A+B)/sinA

Answers

Answered by 217him217

1

Answer:

(sinB/sinA) + 2(cosAcosB - sinAsinB)

=> [ sinB + 2cosAcosBsinA - 2sin²AsinB ] / sinA

=> [ sinB(1-2sin²A) + cosBsin2A ] /sinA

=> [ sinBcos2A + cosBsin2A ]/sinA

=> sin(2A+B)/sinA

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