sine^6theta+cos^6theta=1-3sin^2 theta cos^2 theta
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Hey !!
Sin^6¢ + cos^6¢
(sin²¢)³ + (cos²¢ )³
= (sin²¢ + cos²¢ ) ( sin⁴¢ + cos⁴¢ - sin²¢ ×cos²¢
= ( 1 ² ) (sin²¢ )² +( cos²)² - sin²¢ × cos²¢
= 1 (sin²¢ + cos²¢)² - 2sin²¢ ×cos²¢-sin²¢×cos²¢
•°•(a + b)² - 2ab = a²+ b²
= 1×1 - 3sin²¢cos²¢
= 1 - 3sin²¢ cos²¢ prooved
Hope it helps you !!
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@@Rajukumar 111
Sin^6¢ + cos^6¢
(sin²¢)³ + (cos²¢ )³
= (sin²¢ + cos²¢ ) ( sin⁴¢ + cos⁴¢ - sin²¢ ×cos²¢
= ( 1 ² ) (sin²¢ )² +( cos²)² - sin²¢ × cos²¢
= 1 (sin²¢ + cos²¢)² - 2sin²¢ ×cos²¢-sin²¢×cos²¢
•°•(a + b)² - 2ab = a²+ b²
= 1×1 - 3sin²¢cos²¢
= 1 - 3sin²¢ cos²¢ prooved
Hope it helps you !!
@@@@@@@@@@@@@@@
@@Rajukumar 111
thanks
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