Math, asked by kfv134, 5 months ago

sine B = 1/ root2, find value of tan B + cot B

1
2
root3 + 1/root3
1/4​

Answers

Answered by digitalboy2131
1

Answer:

2

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Step-by-step explanation:

tanB + cotB

=sinB/cosB + cosB/sinB

=(sin^2B + cos^2B)/sinBcosB

=1/sinBcosB

we know that sin2B = 2sinBcosB

=> sinBcosB=sin2B/2

= 2/sin2B

angle B will be 45 degree because sin45= 1/√2

= 2/sin90

=2/1

=2

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