Math, asked by camboloa, 8 months ago

single log log12-2log2-log3

Answers

Answered by shinchan4448
0

Step-by-step explanation:

2log3−1/2log16+log12

Let simplify the expressions into single logarithm,

2log3−1/2log16+log12=2log3−1/2log42+log12

=2log3−log4+log12

=log32−log4+log12

=log(9×12)/4

=log(9×3)

=log27

Similar questions