Math, asked by RabiIslam1250, 1 year ago

Sinh 3x=4sinh^3x+3sinhx

Answers

Answered by Anonymous
24
Heya Friend !!

Please view the solution in the attachment .

hope it helps :)
Attachments:

Silvershades02: hlo
Answered by divyagupta2
21
HIII DEAR❤❤❤❤❤

Given equation :

sinh(3x) = 3*sinh(x) + 4*sinh^3(x)

Lets prove the LHS,

LHS = sinh(3x)

= sinh(2x+x)

= sinh(2x)*cosh(x) + cosh(2x)*sinh(x) [standard identity]

= 2 * sinh(x) * cosh(x) * cosh(x) + (cosh^2(x) + sinh^2(x))sinh(x

= 2 * sinh(x) * cosh^2(x) + (1+sinh^2(x)+sinh^2(x)) sinh(x) {cosh^2(x)

=1+sinh^2(x)} =

2sinh(x) (1 + sinh^2(x)) + (1+2sinh^2(x))sinh(x)

= 2sinh(x) + 2sinh^3(x) + sinh(x) + 2sinh^3(x) = 3sinh(x) + 4sinh^3(x) [RHS as required]

HOPE IT HELPS U....!!

Silvershades02: hlo
Silvershades02: ur intro
Similar questions