Question

sinh x=3/4
cosh(2x)and sinh(2x).​

Answer 1

Answer:

heres your answer:-

sinh x = 3k/4k

(sin theeta = P/H) P=3k and H=4k

(cos theeta = B/H) B=?

•by pytogorus theorum we can find the base (B)

H²=P²+B²

(4k)²= (3k)² + B²

16k² = 9k² +B²

16k²-9k² =B²

7k²=B²

√7k²=B

k√7=B

putting the value in the given eq....