sinh x=3/4
cosh(2x)and sinh(2x).
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heres your answer:-
sinh x = 3k/4k
(sin theeta = P/H) P=3k and H=4k
(cos theeta = B/H) B=?
•by pytogorus theorum we can find the base (B)
H²=P²+B²
(4k)²= (3k)² + B²
16k² = 9k² +B²
16k²-9k² =B²
7k²=B²
√7k²=B
k√7=B
putting the value in the given eq....
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