Math, asked by Agaam, 10 months ago

Sino=a/ √a²+b² then fin cos o and tan o

Answers

Answered by Payelpati2003
3

Answer:

cosФ = b/√(a²+b²)

tanФ = a/b

Step-by-step explanation:

sinФ = a/√a²+b²

cosФ = √1-sin²Ф

         = √1- (a²/a²+b²)

         = √(a²+b²-a²)/(a²+b²)

         = √b²/(a²+b²)

         =b/√a²+b²

tanФ = sinФ/cosФ

         = (a/√a²+b²)÷(b/√a²+b²)

         =a/b

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