Math, asked by saarthak74, 9 months ago

(sino+coseco)^2 + (coso+seco)^2 = 7 + tano +coto​

Answers

Answered by vswamy756
8

Answer:

Step-by-step explanation:

L.H.S=(sin o + cosec o)²+(cos o+sec o)²

        =sin²o+cosec²o+2 sin o cosec o + cos²o+sec²o+2 cos o sec o

we know that

sin o=1/cosec o and cos o=1/sec o

         =sin²o+cosec²o+2+cos²o+sec²o+2

         =sin²o+cos²o+cosec²o+sec²o+4

          =1+1+cot²o+1+tan²o+4

          =7+tan²o+cot²o

hope you understand

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Answered by yuvirana9569
0
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