Question

sinO-cosO+1/sinO+cosO-1=1/secO-tanO​

Answer 1

Step-by-step explanation:

sin-cos+1/sin+cos-1

devide by cos in each term

tan+sec-1/tan-sec+1

=(sec+tan)-(sec²-tan²)/(tan-sec+1)

=(sec+tan)(1-sec+tan)/(tan-sec+1)

=sec+tan

=1/sec-tan