Math, asked by harpreetsingh93, 11 months ago

(sino+coso)^2+(sino-coso)^2=2​

Answers

Answered by Ishwarya12
4

Answer:

Lhs:

(Sino+coso)²+(sino-coso)²

=sin²o+cos²o+2sino.coso+sin²o+cos²o-2sino.coso

=1+1

=2=Rhs

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Answered by sabrinanandini2
2

\huge{\green{\sf{SOLUTION:-}}}

(sin¤ + cos¤)² + (sin¤ - cos¤)²

= sin²¤ + 2sin¤cos¤ + cos²¤ + sin²¤ - 2sin¤cos¤ + cos²¤

= (sin²¤ + cos²¤) + (sin²¤ + cos²¤) + (2sin¤cos¤ - 2sin¤cos¤)

= 1 +1

= 2

Hence Proved

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