(sino+coso)^2+(sino-coso)^2=2
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Answered by
4
Answer:
Lhs:
(Sino+coso)²+(sino-coso)²
=sin²o+cos²o+2sino.coso+sin²o+cos²o-2sino.coso
=1+1
=2=Rhs
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Answered by
2
(sin¤ + cos¤)² + (sin¤ - cos¤)²
= sin²¤ + 2sin¤cos¤ + cos²¤ + sin²¤ - 2sin¤cos¤ + cos²¤
= (sin²¤ + cos²¤) + (sin²¤ + cos²¤) + (2sin¤cos¤ - 2sin¤cos¤)
= 1 +1
= 2
Hence Proved
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