Question

(sinO+cosO)square = 1+sin2O
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Answer 1

Answer:

Let a be the length of the side of a triangle opposite from the angle θ, b the length of the side adjacent to the angle, and c the length of the hypotenuse. Then, sin2θ+cos2θ=(ac)2+(bc)2=a2c2+b2c2=a2+b2c2=c2c2=1.