Sino+coss
=3 then
Sino-coso
Find [sento-costo] = ?
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Click here to get an answer to your question ✍️ If sintheta - costheta = 0 , then the value of (sin^4theta + cos^4theta) is.
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From the above equation, we get costheta = sintheta Hence theta = 45^0 Therefore sin^4theta + cos^4theta = sin^445^0 + cos^445^0 = 2 × (1√(2))^4 = 2 × 14 = 12
Missing: [sinto- | Must include: [sinto-
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