sinp=cosq prove p+q=90
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Answer:
P and Q are acute angles.
To prove :-
p + q = 90°
Proof :-
sinP - cosQ = 0
⇒sinP = cosQ
⇒sinP = sin(90°-Q)
(base is same)
⇒P = 90° - Q
⇒P + Q = 90°
Thus proved!
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