Question

(sinQ +1 +CosQ ) (sinQ -1 +CosQ). secQ cosecQ =2​

Answer 1

Step-by-step explanation:

(sinQ+cosQ+1) (sinQ+cosQ-1)secQcosecQ

={(sinQ+cosQ)²-1²} secQcosecQ

={1+2sinQcosQ-1) secQcosecQ

=2sinQcosQsecQcosecQ

=2

Answer 2

Answer:

Step-by-step explanation:

To prove ,

(sinQ + 1 + cosQ ) (sinQ - 1 + cosQ) secQ cosecQ = 2

LHS

( sinQ + cosQ + 1 ) ( sin Q + cos Q + 1 ) secQ cosecQ .

{(sinQ + cosQ )² - 1²} secQ cosecQ

{sinQ² + cosQ² + 2 sinQ cosQ - 1} secQ cosecQ

{1 - 1 + 2 sinQ cosQ} $\frac{1}{sinQ} \frac{1}{cosQ}$ = 2

∴ LHS = RHS