Question

sinQ/√1-sin square Q

Answer 1

the ansr if the q is : tanQ SECQ

Answer 2

${ (\sin(q) )}^{2} + {( \cos(q))}^{2} = 1 \\ now \\ \frac{ \sin(q) }{ \sqrt{1 - {( \sin(q)) }^{2} } } \\ = \frac{ \sin(q) }{ \sqrt{ {( \cos(q)) }^{2}} } \\ = \frac{ \sin(q) }{ \cos(q) } \\ = \tan(q)$
hope it helps