sinQ + cosQ = 2 then find sin6Q
Answers
Answered by
15
Given
=> sinQ + cosQ = 2
squaring both sides
=> (sinQ + cosQ)² = 2²
=> sin²Q + cos²Q + 2sinQ.cosQ = 4
_____[sin²α+cos²α = 1]
=> 1 + 2 sinQ.cosQ = 4
=> 2sinQ.cosQ = 3
=> sin2Q = 3
_______[2sinα.cosα=sin2α]
=> 2Q = sin^-1(3)
-__-________
then
=> sin6Q = sin3(2Q)
=> sin6Q = sin3sin^-1(3)
_________________[ANSWER]
=> sinQ + cosQ = 2
squaring both sides
=> (sinQ + cosQ)² = 2²
=> sin²Q + cos²Q + 2sinQ.cosQ = 4
_____[sin²α+cos²α = 1]
=> 1 + 2 sinQ.cosQ = 4
=> 2sinQ.cosQ = 3
=> sin2Q = 3
_______[2sinα.cosα=sin2α]
=> 2Q = sin^-1(3)
-__-________
then
=> sin6Q = sin3(2Q)
=> sin6Q = sin3sin^-1(3)
_________________[ANSWER]
Anonymous:
Amazing answer mere mendhak. ;)
Outstanding answer mere natkhat bhaiya... :)
theku @shasi... my chipkli... xD
theku @akhlaka... my Chikku... xD
Wloo bhaiya.. :)
Similar questions