Math, asked by anshnagpal3322, 10 months ago

sinQ + sin2Q=1.Then cos2Q + cos4Q=

Answers

Answered by jivya678
11

The value of \cos^{2}  \theta + \cos^{4} \theta = 1

Step-by-step explanation:

Given that

\ sin \theta + \sin^{2}  \theta = 1

\sin \theta = 1 - \sin^{2}\theta

we know that 1 - \sin^{2} \theta = \cos ^{2}\theta

\sin\theta = \cos^{2} \theta ------- (1)

Thus \cos^{2}  \theta + \cos^{4} \theta may be written as

\cos^{2}  \theta + (\cos^{2} \theta}) ^{2} ------ (2)

Put the value of cos^{2} \theta in above equation. the above equation becomes,

\sin\theta + sin^{2} \theta ------ (3)

We know that \sin\theta + sin^{2} \theta = 1  thus

\cos^{2}  \theta + \cos^{4} \theta = 1

Thus the value of \cos^{2}  \theta + \cos^{4} \theta = 1

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