Question

Sinsin^2acos^2b+cos^2a sin^2b+cos^2a cos^2b+sin^2asin^2b=1 prove this

Answer 1

Step-by-step explanation:

attchment help u if u have any doubt comment

Answer 2

Answer:

To prove,

$sin^{2}acos^{2} b+cos^{2}asin^{2}b+cos^{2}acos^{2}b+sin^{2}asin^{2}b=1$

LHS

⇒ $sin^{2}a(cos^{2}b+sin^{2}b)+cos^{2}a(sin^{2}b+cos^{2}b)$

We know that,

$sin^{2}\theta+cos^{2}\theta=1$

Therefore,

$sin^{2}a(1)+cos^{2}a(1)$

⇒ $sin^{2} a+cos^{2}a$

⇒ $1$ = RHS

Hence, Proved.

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