Math, asked by spshah3004, 1 year ago

Sinteta+sin3theta+sin5theta/costeta+cos3teta+cos5teta=tan3theta

Answers

Answered by sandy1816

0

Step-by-step explanation:

sinA+sin3A+sin5A/cosA+cos3A+cos5A

=(sin5A+sinA)+sin3A/ cos5A+cosA+cos3A

=2sin3Acos2A+sin3A/ 2cos3Acos2A+cos3A

=sin3A(2cos2A+1)/cos3A(2cos2A+1)

=sin3A/cos3A

=tan3A

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