sintheeta-costheeta=1/2 to
(sintheeta+costheeta)=what
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Answer:
sintheeta-costheeta=1/2
sintheeta+costheeta=+✓7/2 (or)
sintheeta+costheeta=-✓7/2
Step-by-step explanation:
Given that sinθ-cosθ=1/2
now squaring both side we have
(sinθ-cosθ) ^2 =1/ 2 ^2
sin ^2 θ+cos ^2 θ-2sinθcosθ=1/4
1-2sinθcosθ=1 /4 (sin ^2 θ+cos^ 2 θ=1)
2sinθcosθ=3/4
consider,
sin ^2 θ+cos ^2 θ+2sinθcosθ= A^2
1+3/4=A^2
7/4=A^2
+✓7/2 = A or -✓7/2 = A
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