Question

Sintheta-costheta+1/sintheta+costheta-1=1/sec theta-tan theta

Answer 1

Step-by-step explanation:

LHS

devide cosA in both numerator & denominator

tanA-1+secA/tanA+1-secA

={(tanA-secA)-1}(tanA-secA)/ (tanA-secA+1)(tanA-secA)

=tan²A-sec²A-(tanA-secA)/ (tanA-secA+1)(tanA-secA)

=-1-tanA+secA/(tanA-secA+1)(tanA-secA)

=-1/tanA-secA

=1/secA-tanA

RHS