Question

sintheta equsl to 1​

Answer 1

Answer:

Hence, the general solution of sin θ = 1 is θ = (4n + 1)π2, n ∈ Z. Therefore, either, 2 sin x + 3 = 0 ⇒ sin x = - 32, Which is impossible since the numerical value of sin x cannot be greater than 1. We know that the general solution of sin θ = 1 is θ = (4n + 1)π2, n ∈ Z. Therefore, x = (4n + 1)π2

Answer 2

Step-by-step explanation:

Hence, the general solution of sin θ = 1 is θ = (4n + 1)π2, n ∈ Z. Therefore, either, 2 sin x + 3 = 0 ⇒ sin x = - 32, Which is impossible since the numerical value of sin x cannot be greater than 1. We know that the general solution of sin θ = 1 is θ = (4n + 1)π2, n ∈ Z. Therefore, x = (4n + 1)π2 ……………