Question

sintheta/x= costheta/y

Answer 1

$\underline{\underline{\huge\mathfrak{Solution:-}}}$

sin theta/x = cos theta/y

sin theta/cos theta = x/y

tan theta = x/y

sin theta = x/root(x2+y2) and cos theta

= y/root(x2+y2)

sin theta – cos theta = (x-y)/root(x2+y2

Answer 2

HEY MATE!!!

sin theta/x = cos theta/y

sin theta/cos theta = x/y

tan theta = x/y 

sin theta = x/root(x2+y2) and cos theta 

y/root(x^2+y^2)

sin theta – cos theta = (x-y)/root(x^2+y^2)

HOPE IT HELPS YOU!!!