Question

(sintita+cosectita)2+(costita+sectita)2-(tan2tita+cot2tita)=solve it ​

Answer 1

Answer:

$\huge \: trigonometric \: formula$

$LHS \\ ( \sinθ + \cos \: ecθ) + \\ (cos \: θ + secθ \: ) = \sin ^{2} + cos \: ec ^{2} θ + \\ 2 \: + cos^{2} θ + sec ^{2} θ + 2 \\ \\ = 4 + 1 + 1 + tan ^{2} θ + 1 + cot ^{2} θ</p><p> \\ (sinθ+cos \: ecθ)+(cosθ+secθ) \\ = 7 + tan ^{2} θ + cot^{2} θ$