Physics, asked by patilk2107, 1 month ago

sinusoidal modulating waveform of amplitude 5 V and a frequency of 2 KHz is applied to FM generator, which has a frequency sensitivity of 40 Hz/volt. Calculate the frequency deviation, modulation index, and bandwidth.​

Answers

Answered by divyanshbansal25
2

Answer:

Given, the amplitude of modulating signal, Am=5V

Frequency of modulating signal, fm=2KHz

Frequency sensitivity, kf=40Hz/volt

We know the formula for Frequency deviation as

Δf=kfAm

Substitute kf and Am values in the above formula.

Δf=40×5=200Hz

Therefore, frequency deviation, Δf is 200Hz

The formula for modulation index is

β=Δffm

Substitute Δf and fm values in the above formula.

β=2002×1000=0.1

Here, the value of modulation index, β is 0.1, which is less than one. Hence, it is Narrow Band FM.

The formula for Bandwidth of Narrow Band FM is the same as that of AM wave.

BW=2fm

Substitute fm value in the above formula.

BW=2×2K=4KHz

Therefore, the bandwidth of Narrow Band FM wave is 4KHz.

Explanation:

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