Question

sinx=0.6 then sin90-x​

Answer 1

Answer:

Step-by-step explanation:

Given since=0.6

sin(90-x)=cosx

we know that sin^2(x)+cos^2(x)=1

(0.6)^2 + cos^2 (x)= 1

0.36+ cos^2 (x)=1

cos^2(x) = 0.64

cosx= 0.8

cos x = sin (90-x) = 0.8