sinx = 0 => x = nπ as I learnt,
but x = sin^-1(0) => x = 0 since the range of arcsinx is [-π/2, π/2]. So, sin^-1(0) has to be in between [-π/2, π/2], that's why 0.
Aren't these two statements contradictory ?
Where am I going wrong ?
Answers
Answered by
1
Answer:
When we are talking about sinx, it is not a function, it is a type of relation so there are no conditions on it's domain and range. But arcsinx is a function, so for one value of x there must be one and only one value of arcsinx(by definition of function) and that is why we limit the range to -π/2,π/2 as it takes all values from -1 to 1
Answered by
1
Answer:
At number line ,negative is less than zero
that's why 0 is lie between -π/2 and π/2.
range of sin X is -π/2 to π/2 .
Similar questions