Question

sinx/1+cos²xdx with upper limit π/2 and lower limit 0​

Answer 1

Answer:

π / 4

Step-by-step explanation:

Solution----->

1) Plzzz see the attachmet

2) To solve the intregation , we apply a substitution which is as follows ,

Let , Cosx = t

Differentiating with respect to x , we get,

=> - Sinx dx = dt

=> Sinx dx = - dt

Then we find new limits

If , x = 0 , t = Cos0 = 1

If , x = π / 2 , t = Cos π/2 = 0

So lower limit is 1 and upper limit is 0

3) We know that,

∫ dx / ( 1 + x² ) = tan⁻¹ x + C

Applying it and putting limits we get, answer