Question

sinx/1-cosx +cosx/1-tanx​

Answer 1

Step-by-step explanation:

How do you prove that (sinx1−cotx)+(cosx1−tanx)=cosx+sinx ?

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Start from the left-hand side. Since

1−cotx=1−cosxsinx=sinx−cosxsinx

and, similarly,

1−tanx=cosx−sinxcosx

the left-hand side can be written

sin2xsinx−cosx+cos2xcosx−sinx

Using the common denominator sinx−cosx , we get

sin2x−cos2xsinx−cosx

and the conclusion is at one step