sinx * 1 =? pls answer
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The answer is sin x as anything * 1 equals itself.
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Answer:
sinx-cosx+1/ sinx+cosx -1
=(sinx-cosx+1)x(sinx +cosx +1) / (sinx+cosx - 1)x(sinx +cosx +1)
=(sinx +1)sq. - (cosx)sq./ (sinx +cosx) sq. - (1)sq.
=sinsq.x+2sinx+1-cossq.x/ sinsq.x+cossq.x+2sinxcosx-1
=2sinsq.x+2sinx/ 2sinxcosx
=2sinx(sinx +1)/ 2sinxcosx
=sinx+1/cosx =(1+sinx)x(1-sinx)/ (cosx) x(1-sinx)
=cosx/(1-sinx) (dividing num. and den. by cosx) =1/secx-tanx PROVED
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