Sinx=4/5 then tanx/cotx=?
Answers
Answered by
6
given,
sin x = 4/5 =opp/ hyp
adj = 3 ( pythagorean triplet)
or
adj ²= hyp² - opp²
adj² = 5² - 4²
adj² = 25 - 16
adj² = 9
adj = √9 = 3
now,
tan x = opp/ adj
= 4/3
cot x = 1/ tanx = 1/ (4/3)
= 3/4
then,
tan x/ cot x =( 4/3) / (3/4)
= 16/9
sin x = 4/5 =opp/ hyp
adj = 3 ( pythagorean triplet)
or
adj ²= hyp² - opp²
adj² = 5² - 4²
adj² = 25 - 16
adj² = 9
adj = √9 = 3
now,
tan x = opp/ adj
= 4/3
cot x = 1/ tanx = 1/ (4/3)
= 3/4
then,
tan x/ cot x =( 4/3) / (3/4)
= 16/9
Answered by
4
hope this helps you.
its with diagram and easy process
its with diagram and easy process
Attachments:
Similar questions