Question

sinx + cosecx = 2 then find sin¹⁹x+ cosec¹⁹x.​

Answer 1

Answer:

2

Step-by-step explanation:

sinx + cosecx = 2

sinx + $\frac{1}{sinx}$  = 2

sin² x + 1 = 2sinx

sin² x − 2sinx + 1 = 0

(sinx−1)² = 0

sinx = 1 , cosecx = 1

$sin^{19}$x +  $cosec^{19}$x=2