Question

sinx + cosecx =2, then sin^n x + cosec^n x

Answer 1

Answer:

Sinx + cosecx =2, then sin^n x + cosec^n x

Step-by-step explanation:

Then the value of Sin n+cos n=2

Answer 2

Answer:

2

Step-by-step explanation:

sin x + cosec x =2

sin x + 1/sinx=2

Lets take L.C.M sinx then,

(sin^2 x + 1)/ sin x = 2

sin ^2 x + 1 = 2 sin x

sin^2 x - 2 sin x + 1 = 0

(sin x - 1)^ 2 = 0

sin^2 x = 1

sin 90 = 1

x=90

1 ^2 = 1

1^3=1 and so on

so sin^2 90 + cosec^n 90 = 2