Math, asked by madansuthar8753, 1 year ago

sinx-cosx+1/sinx+cosx+1=1+sinx/cosx

Answers

Answered by Anonymous
8

Answer:

Step-by-step explanation:

(s-c-1)(s+c-1)/(s+c+1)(s+c-1)

=(s-1-c)(s-1+c)/(s+c)²-1

={(s-1)²-c²}/(s²+c²)+2sc-1

=s²+1–2s-c²/1+2sc-1

=s²+1–2s-(1-s²)/2sc

=2s²-2s/2sc...÷(2s)→

=(s-1)/c

=(s/c)-(1/c)

=tanx-secx

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