Question

(sinx)(cotx+cosx tanx)=cosx+sin2x​

Answer 1

Answer:

Isabelle,

 

Don't let the cotangent & tangent scare you off.  Just change everything to Sines & Cosines and work through the math.

 

Remember that tan x = sin x / cos x    and  cot x = 1/ tan x  = cos x / sin x.

 

So:  (sin x) (cot x + cos x tan x) = sin x (cos x/ sin x + cos x sin x/ cos x)

                                                = ( cos x + sin 2 x)

 

Answer 2

Answer:

Step-by-step explanation:

sinx(cotx + cosx * sinx/cosx)

sinx( cotx + sinx)

sinx(cosx/sinx + sinx)

cosx + sin2x

HENCE PROVED

LHS = RHS