SinX = KsinY. Prove tan([(X-Y)/2]=[(K-1)/(K+1)tan[(X+Y)/2]
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Step-by-step explanation:
f sinx = ksiny then show that tan(x-y/2) = (k-1/k+1)tan(x+y/2)
Answered by
3
Answer:
f sinx= ksiny Then show that tan x-y/2=k-1/k+1 tan x+y/2
I think so this is the answer.
Please reply is this right or wrong
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