Math, asked by rajkumarbhuniyakgp, 9 months ago

sinx+secx.cosx+cosecx darivative​

Answers

Answered by tanisksaxena2020
0

Answer:

sinx+ secx. cos x +cosecx

= d/dx( sinx+ sec x. cos x +cosec x)

= d/dx(sin x +1/cos x. cos x + cosec x)

= d/dx( sin x + 1 + cosec x )

= d/dx sin x + 0 + d /dx(cosec x)

= cosx + (- cosec x. cot x)

= cos x - cosec x. cot x

= cos x - cos x .cosec^2 x

= cos x ( 1 - cosec ^2 x)

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hope it helps

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