Math, asked by Itsmeaditya2003, 1 year ago

Sinx.sin(60+x).sin(60-x)

Answers

Answered by benhurmuthu
3

Step-by-step explanation:

sin x(sin60cosx+cos 60sinx)(sin60cosx-cos60sinx)

sinx(√3/2cos x+1/2sin x)(√3/2cos x-1/2 sinx)

(a+b)(a-b)=a²-b²

sin x(3/4 cos²x-1/4 sin²x)

sin x(3cos²x-sin²x/4)

sin x(3(1-sin²x)-sin²x)/4

sin x(3-3sin²x-sin²x)/4

sin x(3-4sin²x)/4

3/4 sin x - sin³ x

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