Question

sinx sin2x+sinx .4sinx +sinx - sin6x =​

Answer 1

Answer:

sin2x+sin4x+sin6x=(1+2cos2x)sin4x

Using sum to product identities

LHS=sin6x+sin2x+sin4x

sinα+sinβ=2 sin⁡((α+β)/2) cos⁡((α-β)/2)

LHS=sin4x+2 sin⁡((6x+2x)/2) cos⁡((6x-2x)/2)

=sin4x+(2 sin⁡4xcos2x)

=sin4x(1+2cos2x)

Step-by-step explanation:

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