sinx+sin3x+sin5x=0 . solve the equation and give the general solution
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Step-by-step explanation:
Trigo equation..... =____=
sinx + sin3x + sin5x =0
sinx + sin5x + sin3x = 0
2sin 3x cos 2x + sin3x =0
sin3x ( 2 cos2x +1) = 0
So we have two cases right here
Case -1
sin3x = 0
3x = nπ +(-1)^n
(we didn't considered alpha here as
sin function is 0 at 0)
x = nπ/3 + (-1)^n
Case-2
cos2x = -1/2 = 5π/6
2x = 2nπ + 5π/6
x = nπ + 5π/12
Hope it helps uh!
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