Math, asked by shreyabvm, 10 months ago

sinx+sin3x+sin5x=0 . solve the equation and give the general solution

Answers

Answered by Anonymous
0

Step-by-step explanation:

Trigo equation..... =____=

sinx + sin3x + sin5x =0

sinx + sin5x + sin3x = 0

2sin 3x cos 2x + sin3x =0

sin3x ( 2 cos2x +1) = 0

So we have two cases right here

Case -1

sin3x = 0

3x = nπ +(-1)^n

(we didn't considered alpha here as

sin function is 0 at 0)

x = nπ/3 + (-1)^n

Case-2

cos2x = -1/2 = 5π/6

2x = 2nπ + 5π/6

x = nπ + 5π/12

Hope it helps uh!

Answered by rishu6845
3

Answer:

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