sinx-sin3x+sin5x-sin 7x
= cot 2x
cosx-cos3x-cos5x+cos 7
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Answer:
Answer
cosx−cos3x−cos5x+cos7x
sinx−sin3x+sin5x−sin7x
=
(cosx−cos3x)−(cosx−cos7x)
(sinx−sin3x)+(sin5x−sin7x)
=
2sin2xsinx−2sin6xsinx
2cos2xsin(−x)+2cos6xsin(−x)
2sinx[sin2x−sin6x]
−2sin(x)[cos2+cos6x]
2cos4(x)sin(−2x)
−2cos4(x)cos2x
=cot(2x)
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