Question

Sinx + sinx/coax - cos 3x = cot x. Prove it.. I want full description. Otherwise you'll be reported.​

Answer 1

Correction in Question :-

$\bf \frac{sinx + sin3x }{cos x - cos 3x} = cot x\\ \\ \cr WE\ KNOW\ THAT \\ \boxed{ \red{ \sf \: sin 3x = 3 sin x - 4sin³x}} \\ \boxed{ \red{ \sf cos 3x = 3 cos x - 4cos³x }}\\ \\ \\ \\ \tt \frac{ sinx + 3sinx - 4sin³x }{ cos x + 3cos x - 4cos³x } \\ \\ \tt \frac{ 4sinx - 4sin³x }{ 4cosx - 4cos³x } \\ \\ \tt \frac{4sinx (1 - sin²x) }{ 4cosx(1 - cos²x)} \\ \\ \tt \frac{ 4sinx (cos²x) }{ 4cosx(sin²x)} \\ \\ \tt \: \frac{(cosx) }{ (sinx)} \\ \\ \boxed{ \bold {\pmb{cot x}}}$

Answer 2

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