Sipliting the middle term 2x^2+1x-15
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2x^2 +6x-5x -15
2x(x+3)-5(x+3)
(2x-5)(x+3)
2x(x+3)-5(x+3)
(2x-5)(x+3)
nobee:
Thanks
Answered by
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Here Is Your Answer☺️
2x^2+1x-15
→2x^2+6x-5x-15
→2x(x+3)-5(x+3)
→(x+3)(2x-5)
Now,
(x+3)=0
→x=-3
or,
2x-5=0
→x=5/2
Hope My Answer Helped☺️
2x^2+1x-15
→2x^2+6x-5x-15
→2x(x+3)-5(x+3)
→(x+3)(2x-5)
Now,
(x+3)=0
→x=-3
or,
2x-5=0
→x=5/2
Hope My Answer Helped☺️
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