Math, asked by harshvasava6755, 8 months ago

sir help me please ​

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Answered by kumartejas934
1

Answer:

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Answered by Anonymous
1

Answer:

  \frac{ \frac{4}{tan^{2}60^{o}  }  +  \frac{1}{ {cos}^{2} 30^{o} } - 2 {sin} ^{2} 45^{o}   }{ {sin}^{2} 60 ^{o} +  {cos}^{2} 45^{o}  }   =  \\  \\  \\  =  >  \frac{ \frac{4}{ \sqrt{3}  ^{2}  } +  \frac{1}{ (\frac{ \sqrt{3} }{2} )^{2} } -2 \times ( \frac{1}{ \sqrt{2} } )^{2}    }{ { (\frac{ \sqrt{3} }{2}) }^{2} +  { (\frac{1}{ \sqrt{2} } )}^{2}  }  \\  \\  \\  \\  \\  =  >  \frac{ \frac{4}{3} +  \frac{4}{ 3 }    -   \frac{2}{2} }{ \frac{3}{4}  +  \frac{1}{2} }  \\  \\  \\  =  >  \frac{ \frac{8}{3} - 1 }{ \frac{3 + 2}{4} }  \\  \\  \\  =  >  \frac{ \frac{8}{3} -  \frac{1}{1}  }{ \frac{5}{4} }  \\  \\  \\  =  >  \frac{ \frac{8 - 3}{3} }{ \frac{5}{4} }  \\  \\  =  >  \frac{ \frac{5}{3} }{ \frac{5}{4} }  \\  \\  =  >  \frac{5}{3}  \times  \frac{4}{5}  =  \frac{4}{3}  \:  \: ans...

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