Sir how to apper -3ab in (a+b)^3
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Answer:
By algebraic identity:
a³+b³+3a²b+3ab² = (a+b)³
=> a³+b³+3ab(a+b) = (a+b)³
=> a³+b³ = (a+b)³-3ab(a+b)
Therefore,
a³+b³ = (a+b)³-3ab(a+b)
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