Physics, asked by Anonymous, 6 months ago

Sir how to solve this question

full explanation

how many numbers greater than 100,00,00 can be formed by using the digits 1,2,6,2,4,2,4 ?​

Answers

Answered by Anonymous
6

Answer:

We can find the possible numbers to generate using the combinations :

Total=(73)∗(42)∗(21)∗(11)

Explanation:

we have 7 possible positions to distribute our 3 two's, hence (73)

we have 4 possible positions to distribute our 2 four's, hence (42)

we have 2 possible positions to distribute our single zero, hence (21)

we have 1 possible position to distribute our single one, hence (11)

But since the numbers that start with digit 0 are not greater than 1000000, we will have to subtract them:

NumberStartWithZero=(63)∗(32)∗(11)

Total−NumberStartWithZero=360 (after few calculations)

Answered by ravanji786
1
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