Sir how to solve this question
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how many numbers greater than 100,00,00 can be formed by using the digits 1,2,6,2,4,2,4 ?
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Answer:
We can find the possible numbers to generate using the combinations :
Total=(73)∗(42)∗(21)∗(11)
Explanation:
we have 7 possible positions to distribute our 3 two's, hence (73)
we have 4 possible positions to distribute our 2 four's, hence (42)
we have 2 possible positions to distribute our single zero, hence (21)
we have 1 possible position to distribute our single one, hence (11)
But since the numbers that start with digit 0 are not greater than 1000000, we will have to subtract them:
NumberStartWithZero=(63)∗(32)∗(11)
Total−NumberStartWithZero=360 (after few calculations)
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