Question

Sir how to solve this question

how many numbers greater than 100,00,00 can be formed by using the digits 1,2,6,2,4,2,4 ?​

Answer 1

Step-by-step explanation:

We can find the possible numbers to generate using the combinations :

Total=(7/3)∗(4/2)∗(2/1)∗(1/1)

Explanation:

we have 7 possible positions to distribute our 3 two's, hence (7/3)

we have 4 possible positions to distribute our 2 four's, hence (4/2)

we have 2 possible positions to distribute our single zero, hence (2/1)

we have 1 possible position to distribute our single one, hence (1/1)

But since the numbers that start with digit 0 are not greater than 1000000, we will have to subtract them:

NumberStartWithZero=(6/3)∗(3/2)∗(1/1)

Total−NumberStartWithZero=360 (after few calculations)

√\______❤Anushka

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Answer 2

Here we are available with 7 – digits, one 1, three 2’s, one 0 and two 4’s.

Also ,the number 1000000 has 7 digits and we want to form numbers greater than 1000000.     So, the required numbers should also be of 7 digits.

The number of all type of arrangements possible with the given digits is  

                                       

Now these arrangements also include the cases when  0 is at extreme left position which makes the number a 6 digit one. The number of such numbers is  

                                               

Excluding these numbers, we get the required number of numbers = 420 – 60 = 360.