Question

Sir,
Solve the following pair of linear equation by the substitution method √2x+√3y=0,√3x-√8y=0

Answer 1

Answer:

Step-by-step explanation:

Given:

√2x + √3y = 0 _________ (Equation-1)

√3x - √8y = 0 _________ (Equation-2)

In Equation-1

√2x + √3y = 0

√2x = -√3y

x = -√3y/√2 ________ (Equation-3)

In Equation-2

√3x - √8y = 0

√3*(-√3y/√2) - √8y = 0 _________(From Equation-3)

-3y/√2 - √8y = 0

Taking LCM

(-3y - √16y )/√2 = 0

Multiplying both side by √2

-3y - 4y = 0

-7y = 0

y = 0 _________ (Equation-4)

Equation-3

x = √3*y/√2

x = √3*0/√2 _______(From Equation-4)

x = 0

HOPE YOU GAVE GOT YOUR ANSWER